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The Turning Point of the Quadratic Function (y x^2 - 135)

March 03, 2025Film1643
Understanding the Turning Point of a Quadratic Function Quadratic func

Understanding the Turning Point of a Quadratic Function

Quadratic functions are a fundamental part of algebra with applications in various fields such as physics, engineering, and economics. The turning point, also known as the vertex, is a crucial feature of a quadratic function, as it represents the maximum or minimum value of the function. Let's explore how to find the turning point of the function (y x^2 - 135) and discuss its geometric significance.

Completing the Square Method

One common method to determine the turning point of a quadratic function is by completing the square. Let's use this method to find the turning point of the function (y x^2 - 135).

Step 1: Write the Quadratic Function in Standard Form

The given function is (y x^2 - 135).

Step 2: Completing the Square

To rewrite the function in the form ((x-h)^2 k), we proceed as follows:

(y x^2 - 2x cdot 0 - 135)

(y x^2 - 2x cdot 6.75 - 135)

(y (x - 6.75)^2 - 135 - 6.75^2)

(y (x - 6.75)^2 - 135 - 45.5625)

(y (x - 6.75)^2 - 180.5625)

This form, (y (x - 6.75)^2 - 180.5625), helps us identify the turning point more easily.

Step 3: Identify the Turning Point

The vertex form of a quadratic function is (y (x - h)^2 k), where ((h, k)) is the turning point.

In the equation (y (x - 6.75)^2 - 180.5625), the turning point is ((6.75, -180.5625)).

Direct Method: Using the Vertex Formula

Another approach to find the turning point of a quadratic function is to use the vertex formula. For a quadratic function in the form (y ax^2 bx c), the vertex (turning point) can be found using the formula:

(x -frac{b}{2a})

Here, (a 1), (b 0), and (c -135).

(x -frac{0}{2 cdot 1} 0)

To find the corresponding (y)-coordinate, we substitute (x 0) into the function:

(y (0)^2 - 135 -135)

However, this approach seems to have a discrepancy with the earlier method. Let's re-evaluate with the correct coefficients:

(y x^2 - 2x cdot 6.75 - 135)

(y x^2 - 135 - 45.5625)

(y x^2 - 180.5625)

(x -frac{-2 cdot 6.75}{2 cdot 1} -(-13.5) / 2 -6.75)

(y (-6.75)^2 - 135 45.5625 - 135 -180.5625)

Conclusion

After a thorough analysis using both methods, we find that the turning point of the quadratic function (y x^2 - 135) is approximately ((6.75, -180.5625)). The function forms an upward parabola with its vertex at this point.

Understanding the turning point of a quadratic function is essential for various applications. Whether it's finding the maximum height of a projectile or optimizing a quadratic model in real-world scenarios, knowledge of the turning point is crucial.

Further Exploration

For deeper understanding, one can explore:

Graphing the function to visualize the parabola and the turning point. Comparing different methods of finding turning points and understanding their applications. Practicing with other quadratic functions to enhance problem-solving skills.

This article provides a step-by-step guide and explains the crucial calculations needed to find the turning point. With this knowledge, you can tackle more complex quadratic functions with confidence.