Solving the Ratio of Ages: A Comprehensive Guide
Solving the Ratio of Ages: A Comprehensive Guide
Understanding and solving age-related problems, particularly those involving ratios, is a fundamental skill in mathematics. This article provides a detailed step-by-step guide to solving a specific age-related problem, helping you to understand and solve similar problems in the future.
Problem Statement
The ages of A, B, and C are in the ratio 4:5:6. If the sum of their ages is 75 years, what is the age of C?
Solution
To solve this problem, we will follow a structured approach:
Step 1: Understanding the Problem
We are given the ratio of the ages of A, B, and C as 4:5:6. This means:
The age of A is 4 parts. The age of B is 5 parts. The age of C is 6 parts.Let's denote the common factor by 'x'. Therefore, the ages can be represented as:
Age of A 4x Age of B 5x Age of C 6xStep 2: Setting Up the Equation
The problem states that the sum of their ages is 75 years. Therefore, we can set up the equation:
4x 5x 6x 75
Combining the like terms on the left side, we get:
15x 75
To find the value of x, we will divide both sides of the equation by 15:
x 75 / 15
x 5
Step 3: Calculating the Age of C
Now, we know that the age of C is 6x. Substituting the value of x, we get:
Age of C 6 * 5 30 years
Alternative Method (Alternative Solution)
Another way to solve this problem is to directly use the given sum and the total parts of the ratio:
15 parts of the ratio represent 75 years. Therefore:
Age of C (6/15) * 75
Age of C 6 * 5 30 years
Conclusion
The age of C is 30 years. This method can be applied to similar problems where you are given the ratio of ages and the total sum of ages.
Additional Resources
If you would like to learn more about solving age-related problems or need additional practice, consider revisiting the concept of ratio and proportion. Utilizing online resources or educational platforms can provide you with further practice problems and detailed explanations.
Note: This guide is designed to help you solve such problems efficiently. If you have any questions or need further assistance, feel free to ask!
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